The system of equations ax+3y=1 , -12x+ay=2 has _____ solutions for all real values of a.
Answers
Answered by
15
Answer:
Unique solution.
Step-by-step explanation:
ax+3y-1=0
-12x+ay-2=0
a/-12=3/a= -1/-2
By cross multiplying the first and third fractions:
-2a=12
a= -6
By multiplying the second and third fractions:
-6=-a
a=6
We find that there are only 2 values of a.Thus,it forms a unique solution.
Answered by
0
Answer:
ax+3y=a−3
→ax+3y−a+3=0
a
1
=a,b
1
=3,c
1
=−a+3
12x+ay=a
→12x+ay−a=0
a
2
=12,b
2
=a,c
2
=−a
Condition for no solution is
a
2
a
1
=
b
2
b
1
=
c
1
c
1
12
a
=
a
3
=
a
a−3
→a
2
−36
→a=±6
a=+6 is not possibel because it gives
a
2
a
1
=
b
2
b
1
=
c
2
c
1
∴a=−6 is the answer
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