Question

The system of equations r^2+s^2=t and r+s+t=k-3/2 has exactly one solution find k

Answer 1

Step-by-step explanation:

Eliminating t, we get

r+s+r2+s2=k-32

or r2+r+s2+s+3-k2=0

Now for one real solution ′r′

D=0

∴1-4(s2+s+3-k2)=0

∴4s2+4s+5-2k=0

Now for one real solution ′s′

D=0

∴16-16(5-2k)=0

∴1=5-2k

∴k=2