Question

The system of equations x = k1 and y -k2 = 0 have (where k1 and k2 are constants)

Answer 1

$2.3031000K</p><p></p><p>k1 = 1016e−2000/T</p><p>k2 = 1015e−2000/T</p><p></p><p>By taking log on both of them</p><p>⟹logk1=log1016−2.3032000t</p><p>⟹logk2=log1015−2.3031000t</p><p>Now, k1 = k2, Hence from equations T=2.3031000k</p><p></p><p>$