Question

The system shown in the figure is in equilibrium.the maximum value of W,so that the maximum value of static frictional force on 100 kg body is 450N,will be

Answer 1

Answer:

The answer will be 450  N

Explanation:

According to the problem the system is in equilibrium.

Le the tension of 100 kg  block is p1 and as well as w block having the tension of p2

Therefore, let the frictional force initially, = f= p1 = 0

Now it is given that the frictional force, p1 = 450 N

Therefore p2 = w

Now we can use Lami's theorem here

According to the theorem,

p1/sin 135=p2/sin 135=p3/sin 90

So p1=p2

Therefore the  static frictional force is 450 N

Answer 2

Answer: (3) 450 N.

Explanation:

Let the tension in block of mass 100kg be T1, and on block W be T2.

Let T3 be tension on the string attached to wall.

As given in the question that the system is in equilibrium.

So, T1= f 450 N ............(i)

And T2 = W ..........(ii)

applying Lami's theorem,

T1sin 135=T2sin 135=T3sin 90So we get, T1=T2Equating (i) and (ii) we get, W = 450 N.