Question

the t half of a reaction is halved as the initial concentration of the reactant is doubled what is the order of reaction please explain​

Answer 1

t half proportional to 1/C n-1(in power)

let initial concentration =a {t half)1=t

initial concentration =2a,(t half)= t/2

(t half)1/(t half)2= (C2/C1)^n-1

t/t/2=(2a/a)n-1

2=2 ^n-1

n-1=1

n=2

hence the order of reaction is second✌✌