Question

The T.S..A of a right circular cylinder whose height and base radius 40cm and 21cm resp. are

Answer 1

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The T.S.A of a right circular cylinder whose height and base radius 40cm and 21cm respectively are ?

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T.S.A of right circular cylinder is 8052cm²

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• Base radius of cylinder = 21cm
• Height of Cylinder = 40cm

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T.S.A of right circular cylinder

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T.S.A of cylinder =

$\bf \pink{2\pi r(r + h)}$

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In this question, Height and radius of cylinder are given We have to find T.S.A of cylinder

T.S.A of cylinder =

$\bf {2\pi r(r + h)}$

$\bf \implies 2 \times \frac{22}{7} \times 21(21 + 40)$

$\bf \implies 2 \times \frac{22}{7} \times 21 \times 61$

$\bf \implies 2 \times 22 \times 3 \times 61$

$\bf \implies {8052cm}^{2}$

Therefore, Total surface area of cylinder is 8052cm².

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Answer 2

Step-by-step explanation:

T.S.A of right circular cylinder is 8052cm²

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Base radius of cylinder = 21cm

Height of Cylinder = 40cm

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T.S.A of right circular cylinder

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T.S.A of cylinder =

\bf \pink{2\pi r(r + h)}2πr(r+h)

\bf {\underline {\underline{✤ SƠԼƲƬƖƠƝ}}}

✤SƠԼƲƬƖƠƝ

In this question, Height and radius of cylinder are given We have to find T.S.A of cylinder

T.S.A of cylinder =

\bf {2\pi r(r + h)}2πr(r+h)

\bf \implies 2 \times \frac{22}{7} \times 21(21 + 40)⟹2×

7

22

×21(21+40)

\bf \implies 2 \times \frac{22}{7} \times 21 \times 61⟹2×

7

22

×21×61

\bf \implies 2 \times 22 \times 3 \times 61⟹2×22×3×61

{8052cm}^{2}⟹8052cm

2

Therefore, Total surface area of cylinder is 8052cm².