The table below shows all of the possible outcomes for rolling two six-sided number cubes.What is the probability of rolling an even number first and an odd number second?
Answers
Answer:
As two cubes are 6 sided, the total number of possibilities are (6\times6) = 36(6×6)=36
Now in those possibilities the first number will be even and the second number will be odd. If we check the table, such pairs are,
(2,1), (2,3), (2,5), (4,1), (4,3), (4,5), (6,1), (6,3), (6,5)
So, we can see we have total 9 set with the combination of first number even and second number odd. So, the probability of rolling with this combination will be \bold\frac{9}{36}=\frac{1}{4}\bold
Given :
The table below shows all of the possible outcomes for rolling two six-sided number cubes.
A table with 36 possible outcomes.
To Find : What is the probability of rolling an even number first and an odd number second?
1/9
1/6
1/4
1/2
Solution:
1 2 3 4 5 6
1 1,1 1,2 1,3 1,4 1,5 1,6
2 2,1 2,2 2,3 2,4 2,5 2,6
3 3,1 3,2 3,3 3,4 3,5 3,6
4 4,1 4,2 4,3 4,4 4,5 4,6
5 5,1 5,2 5,3 5,4 5,5 5,6
6 6,1 6,2 6,3 6,4 6,5 6,6
an even number first and an odd number second
= { (2 , 1) , ( 2 ,3 ) , ( 2 , 5) , ( 4 , 1) , ( 4 ,3 ) , ( 4 , 5) , ( 6 , 1) , ( 6 , 3) , ( 6 ,5)}
Total 9 case
probability of rolling an even number first and an odd number second = 9/36
= 1/4
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