The table shows the battery life of four different mobile phones:
Mobile Phone Battery Life
Phone Battery Life (hours)
A 20
B 25
C 10
D 18
If 8.45% of the battery life of each mobile phone is used in a day by a typical user, for which mobile phone is 2.1 hours of battery life used in a day?
Phone A
Phone B
Phone C
Phone D
Answers
We have,
Phones with their respective battery life (in hrs) :-
A lasts for 20 hrs
B lasts for 25 hrs
C lasts for 10 hrs
D lasts for 18 hrs
Now, we are to find which mobile phone consumes 2.1 hrs of battery life when 8.45% of the total battery capacity is used.
We can derive the usage duration of each phone as follows:-
Phone A = × hrs = |1.69| hrs = 1.7 hrs
Phone B = × hrs = 21. hrs
Phone C = × hrs = 0.8 hrs
Phone D = × hrs = 1.5 hrs
From among the derived results, we can see that battery usage duration of Phone B is 2.1 hours.
Ans) On using 8.45% of the total battery life, Phone B uses 2.1 hours worth of battery life.
Given :- The table shows the battery life of four different mobile phones :-
Mobile Phone Battery Life (hours)
A 20
B 25
C 10
D 18
If 8.45% of the battery life of each mobile phone is used in a day by a typical user, for which mobile phone is 2.1 hours of battery life used in a day ?
A) Phone A
B)Phone B
C)Phone C
D) Phone D
Solution :-
we need to find , Battery life of which mobile phones 8.45% is equal to 2.1 hours.
So, checking Battery life of each phone we get,
Mobile A :-
→ Battery Life = 20 hours .
So,
→ 8.45% of 20 hours = (8.45 * 20)/100 = 8.45/5 = 1.69 hours.
Mobile B :-
→ Battery Life = 25 hours .
So,
→ 8.45% of 25 hours = (8.45 * 25)/100 = 8.45/4 = 2.11 ≈ 2.1 hours.
Mobile C :-
→ Battery Life = 10 hours .
So,
→ 8.45% of 10 hours = (8.45 * 10)/100 = 8.45/10 = 0.845 hours.
Mobile D :-
→ Battery Life = 18 hours .
So,
→ 8.45% of 18 hours = (8.45 * 18)/100 = 152.1/100 = 1.521 hours.
Therefore, "Phone B" used 2.1 hours of battery life in a day .
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