Math, asked by lrroberts1116, 7 months ago

The table shows the battery life of four different mobile phones:


Mobile Phone Battery Life
Phone Battery Life (hours)
A 20
B 25
C 10
D 18


If 8.45% of the battery life of each mobile phone is used in a day by a typical user, for which mobile phone is 2.1 hours of battery life used in a day?
Phone A
Phone B
Phone C
Phone D

Answers

Answered by Manjula29
1

We have,

Phones with their respective battery life (in hrs) :-

A lasts for 20 hrs

B lasts for 25 hrs

C lasts for 10 hrs

D lasts for 18 hrs

Now, we are to find which mobile phone consumes 2.1 hrs of battery life when 8.45% of the total battery capacity is used.

We can derive the usage duration of each phone as follows:-

Phone A = \frac{8.45}{100} × 20 hrs = |1.69| hrs = 1.7 hrs

Phone B =  \frac{8.45}{100} × 25 hrs = 21. hrs

Phone C =  \frac{8.45}{100} × 10 hrs = 0.8 hrs

Phone D =  \frac{8.45}{100} × 18 hrs = 1.5 hrs

From among the derived results, we can see that battery usage duration of Phone B is 2.1 hours.

Ans) On using 8.45% of the total battery life, Phone B uses 2.1 hours worth of battery life.

Answered by RvChaudharY50
4

Given :- The table shows the battery life of four different mobile phones :-

Mobile Phone Battery Life (hours)

A 20

B 25

C 10

D 18

If 8.45% of the battery life of each mobile phone is used in a day by a typical user, for which mobile phone is 2.1 hours of battery life used in a day ?

A) Phone A

B)Phone B

C)Phone C

D) Phone D

Solution :-

we need to find , Battery life of which mobile phones 8.45% is equal to 2.1 hours.

So, checking Battery life of each phone we get,

Mobile A :-

→ Battery Life = 20 hours .

So,

→ 8.45% of 20 hours = (8.45 * 20)/100 = 8.45/5 = 1.69 hours.

Mobile B :-

→ Battery Life = 25 hours .

So,

→ 8.45% of 25 hours = (8.45 * 25)/100 = 8.45/4 = 2.11 2.1 hours.

Mobile C :-

→ Battery Life = 10 hours .

So,

→ 8.45% of 10 hours = (8.45 * 10)/100 = 8.45/10 = 0.845 hours.

Mobile D :-

→ Battery Life = 18 hours .

So,

→ 8.45% of 18 hours = (8.45 * 18)/100 = 152.1/100 = 1.521 hours.

Therefore, "Phone B" used 2.1 hours of battery life in a day .

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