Question

The take off of boeing 747 is 252km/hr.if it can accelarate at 1.5m/s^2 what should be the minimum length of the runway?

Answer 1

Explanation:

given v=252 km/hr

convert it into m/s so,multiply with 5/18

v=252×5/18

v=70m/s

v^2-u^2=2as

for any flight intial velocity is zero

u=0

70×70=2×3/2×s

s=1633.3m

s=1.6 km approx