Math, asked by preetanmol41631, 11 months ago

The tallest freestanding tower in the world in the cn tower is toronto canada the tower includes a rotating restaurant high above the ground from a distance of 100 metres the angle of elevation of the top of the tower is 60° then angle of elevation to the resident from the same point is 45° how tall is the cn tower how far is the pinnacle of the tower is a restaurant located

Answers

Answered by amitnrw
14

Restaurant is located 100(√3 - 1) m = 73.2 m  below the pinnacle of the tower

Step-by-step explanation:

.the angle of elevation of the restaurant from the same vantage point (100 m Distance)  is 45 degree

=> Tan 45 =  Height of Restaurant from ground / Distance of point from ground

=> 1 =  Height of Restaurant from ground /  100

=> Height of Restaurant from ground = 100 m

the angle of elevation to the pinnacle of the tower = 60°

=> Tan 60 = Height of  pinnacle of the tower / 100

=> √3 = Height of  pinnacle of the tower / 100

=> Height of  pinnacle of the tower = 100√3  m

Restaurant is located  100√3 - 100   = 100(√3 - 1) m = 73.2 m below the pinnacle of the tower

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Answered by anirudhkurup2004
17

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Plz mark asbrainly pz plz

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