Question

The tAngent of the curve Y= 2x^2-x+1 is parallel to the line y = 3x+9 at the point​

Answer 1

We have y = 2x2 - x + 1 ⇒ dy/dx = 4x - 1 We know that this equation gives the slope of tangent to the curve. Since this tangent is parallel to y = 3x + 9, the slope of the tangent is 3 and so 4x - 1= 3 or x =1. Therefore y = 2x2 - x + 1 = 2. Thus, the point (x, y) is (1, 2).