The tangent to the circle at p and q intersect at a point t prove that PQ and OT bisect each other at right angles
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Step-by-step explanation:
angle opt=angle oqt=90 degree
angle t =90 degree(angle sum property)
PTQO is a square(llgm with all angles 90 degree and adjacent sides are equal)
in a square the diagonals are ⊥ bisector
∴pq and ot are perpendiculaer bisector
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