Question

the tangent to the curve y = 2x²-x+1 is parallel to the line y = 3x+9 at the point​

Answer 1

Step-by-step explanation:

Here,

if the we find the slope of

tangent,....

$\frac{dy}{dx} = 4x - 1$

the equation for the tangent is

$y - y1 = \frac{dy}{dx} (x - x1)$

we get..

y = 3x+9 and the slope is 3

so,

$\frac{dy}{dx} = 4x - 1 = 3$

x= 1

now we put value to the 1st equation

and the y =

$y = 2( {1}^{2} ) - 1 + 1$

y = 2

the point is (x,y)= (1,2)

and the tangential equation is y= 3x -1