Question

The tangent to the parabola y² = 4x at the point where it intersects the circle x² + y² = 5 in the first quadrant, passes through the point:
(A) (-1/3, 4/3)
(B) (3/4, 7/4)
(C)
(-1/4, 1/2)
(D) (1/4, 3/4)

Answer 1

Answer:

(B) (3/4,7/4)

Step-by-step explanation:

Given y² =4x ...(1)

and x²+y²=5 ...(2)

for point of intersection x² + 4x – 5 = 0

(x+5)(x+1)=0

x = – 5 x =1

Not possible y = ± 2

Point in IQ (1, 2)

Tangent at (1, 2)

2y = 4(x + 1/2)

y = x + 1 point (3/4, 7/4) lies on tangent.