Question

the Tangential acceleration of the tip of blade is 47.13m/sc2and it's centripetal acceration is 473.9m/sc2.Find the value of linear acceleration of tip of the blade

Answer 1

The value of linear acceleration of tip of the blade is 4.76×10² m/s²

Let us consider the tangential acceleration to be a and the centripetal acceleration to be a'.

Given, a = 47.13m/s² and

a' = 473.9m/s²

We know that the linear acceleration A is given as √[(a²)+ (a')²]

Substituting the values, we get

A = √[(47.13²)+ (473.9')²]

= 4.76×10² m/s²