Question

The tangents from an outside print 'P' to a circle with centre 'O' are PA and PB where
ZAOB = 80°. Then ZAPB is
a) 80°
b) 100°
c) 90°
d) 70°​

Answer 1

Answer:

B) 100°

Step-by-step explanation:

By angle sum property of a quadrilateral

90°+90°+80°+ angle APB=360°

angle APB=360°-260°

angle APB=100°