Question

The tank circuit of L-C oscillator contains a capacitor of 30 μF and an inductor of 27 mH. Find the natural angular frequency of oscillations. [ Ans. 1.111*10³ rads⁻¹]

Answer 1

Answer:

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Answer 2

Answer:

$\ 1.11\times 10^3\ rad/s$

Explanation:

Given,

capacitance of the circuit, C = 30 μF

                                             $=\ 30\times 10^{-6}\ F$

Inductance of the inductor, L = 27 mH

                                                $=\ 27\times 10^{-3} H$

The angular frequency of oscillation of the tank circuit can be given by,

               $\omega\ =\ \dfrac{1}{\sqrt{LC}}$

                              $=\ \dfrac{1}{\sqrt{30\times 10^{-6}\times 27\times 10^{-3}}}$

                              $=\ \dfrac{1}{\sqrt{810\times 10^{-9}}}$

                                $=\ 1.11\times 10^3\ rad/s$

So, the natural angular frequency of oscillations of the tank circuit will be $1.11\times 10^3\ rad/s.$