Math, asked by rameshpriyapathiputt, 5 months ago

the taxi changes in a city comprise of a fixed charges together with the charges for the distance covered for journey of 10km the charges paid is Rs 75 and for a journey of 15km the charge paid is Rs 110 what will a person have to pay for travelling a distance of 25km​

Answers

Answered by mashmellow543
0

Answer:

224

Step-by-step explanation:

Let the fixed charge = Rs x and the charges per km = Rs y Thus, the fixed charge = Rs. x= Rs. 5 and The charge per km = Rs.. y = Rs. 10 People have to pay for traveling a distance of 25 km = x + 25 y = 5 + 25*10 = 5 + 250 Rs 255Read more on Sarthaks.com - https://www.sarthaks.com/2245/taxi-charges-city-consist-fixed-charge-together-with-the-charge-for-the-distance-covered?show=2486#a2486

Answered by Sanket1829
1

Answer:

Rs. 180

Step-by-step explanation:

Let the fixed charges of taxi be Rs x and the running charges be Rs y km/hr.

According to the given condition, we have 0

x+10y=75............(i)

x+15y=110............(ii)

Subtracting equation (ii) from equation (i), we get,

−5y=−35⇒y=7

Putting y=7 in equation (i), we get x=5

∴ Total charges from travelling a distance of 25km

=x+25y

=Rs.(5+25×7)=Rs.180.

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