The taxi charges in a city comprise of a fixed charge together with the charges for the distance covered. For a journey of 10 km the charge paid is Rs. 75 and for a journey of 15 km the charge paid is Rs. 110.Find the fixed charge and charge per km.Hence ,find the charge of cobering a distance of 35km.
Answers
Brainly.in
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vinaysancheti2512
Secondary School Math 5+3 pts
The taxi charges in a city comprise of a fixed charge together with the charges for the distance covered. For a journey of 10 km the charge paid is Rs. 75 and for a journey of 15 km the charge paid is Rs. 110.
(i) What will a person have to pay for travelling a distance of 25 km?
(ii)Which mathematical concept is used in this question?
(iii) What is its value?
Report by Rpoonia443 25.03.2018
Answers
ritik987
Ritik987Virtuoso
Let the fixed charge of taxi be Rs. x per km and the running charge be ` y per km.
According to the question,
x + 10y = 75
x + 15y = 110
Subtracting equation (ii) from equation (i), we get
– 5y = – 35
⟹ y = 7
Putting y = 7 in equation (i), we get x = 5
∴Total charges for travelling a distance of 25 km = x + 25y
= (5 + 25 × 7)
= (5 + 175)
= 180
fixed charge = x
variable charge =₹ y / km
x + 10y= 75....(1)
x+15y = 110....(2)
eq...(1)-(2)
x+10y=75
x+15y=110
- -. -
_________
-5y=-35
y=7
putting value of y in eq....(1)
x+10y=75
x+10×7=75
x+70=75
x=5
hence,
fixed charge=x=₹5
variable charge=₹y/km=₹7/km