The taxi charges in a city comprise of a fixed charge together with the charges for the distance covered. For a journey of 10 km the charge paid is Rs. 75 and for a journey of 15 km the charge paid is Rs. 110. What will a person have to pay for travelling a distance of 25 km ?
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Answered by
3
Answer:
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your answer is here !
Step-by-step explanation:
Let the fixed charge of taxi be Rs. x per km and the running charge be Rs y per km.
According to the question,
x + 10y = 75
x + 15y = 110
Subtracting equation (ii) from equation (i), we get
– 5y = – 35
⟹ y = 7
Putting y = 7 in equation (i), we get x = 5
∴Total charges for travelling a distance of 25 km = x + 25y
= (5 + 25 × 7)
= (5 + 175)
= Rs 180
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Answered by
1
Answer:
- Here it is................................!
- Let the fixed charge be 'x' and running charge be 'y'.-
- ATQ,
- 10x+y=75
- 15x+y=110
- x=5 y=7
Now, for a distance of 25 km total charges will be >> x+25y= 5+25(7) = 180 rs
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