The taxi charges in a city comprise of a fixed charge together with the charges for the distance covered. For a journey of 10 km the charge paid is Rs. 75 and for a journey of 15 km the charge paid is Rs. 110. What will a person have to pay for travelling a distance of 25 km?
Answers
Let the fixed charges of taxi be Rs x and the running charges be Rs y km/hr.
According to the given condition, we have 0
x+10y=75 .(i)
x+15y=110 .(ii)
Subtracting equation (ii) from equation (i), we get
−5y=−35⇒y=7
Putting y=7 in equation (i), we get x=5
∴ Total charges from travelling a distance of 25km
=x+25y
=Rs.(5+25×7)=Rs.180.
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Answer:
aⁿˢʷEʳ
Let the fixed charge of taxi be Rs. x per km and the running charge be Rs y per km.
According to the question,
x + 10y = 75
x + 15y = 110
Subtracting equation (ii) from equation (i), we get
– 5y = – 35
⟹ y = 7
Putting y = 7 in equation (i), we get x = 5
∴Total charges for travelling a distance of 25 km = x + 25y
= (5 + 25 × 7)
= (5 + 175)
= Rs 180