Question

The taxi charges in a city comprise of a fixed charge together with the charges for the distance covered. For a journey of 10 km the charge paid is Rs. 75 and for a journey of 15 km the charge paid is Rs. 110.

(i) What will a person have to pay for travelling a distance of 25 km?

(ii)Which mathematical concept is used in this question?

(iii) What is its value?

Answer 1

Let the fixed charge of taxi be Rs. x per km and the running charge be ` y per km.

According to the question,

x + 10y = 75

x + 15y = 110

Subtracting equation (ii) from equation (i), we get

– 5y = – 35

⟹ y = 7

Putting y = 7 in equation (i), we get x = 5

∴Total charges for travelling a distance of 25 km = x + 25y

= (5 + 25 × 7)

= (5 + 175)

= 180

Answer 2

Answer:

180

Step-by-step explanation:

Given:-a journey of 10 km the charge paid is Rs. 75 and for a journey of 15 km the charge paid is Rs. 110.

To Find:-What will a person have to pay for travelling a distance of 25 km?

Solution:-

Let the fixed charge of taxi be Rs. x per km and the running charge be ` y per km.

so,

x + 10y = 75....eq(i)

x + 15y = 110......ew(ii)

Subtracting equation (ii) from equation (i), we get

– 5y = – 35

⟹ y = 7

Putting the value of y = 7 in equation (i), we get x = 5

∴Total charges for travelling a distance of 25 km = x + 25y

= (5 + 25 × 7)

= (5 + 175)

= 180

#SPJ2