Question

the taxi charges in a city comprise of fixed charges together with the charges for the distance covered for a journey of 10 km the charge is 75 for journey of 15 km charge paid is 110 what will a person pay for travelling a distance of 25 km

Answer 1

let the fixed charge be x
let the charge let distance be y
so ATQ
$x + 10y = 75.............(1) \\ x + 15y = 110............(2) \\ (1) - (2) \\ - 5y = - 35 \\ 5y = 35 \\ y = 7$
Putting y in equation 1 we get
$x + 10y = 75 \\ x + 10(7) = 75 \\ x = 5$
For travelling 25 km
$x + 25y = 5 + 25(7) \\ = 5 +175 = 180$

Answer 2

hope it's helpful for u...