Question

the taxi charges in a city consist of a fixed charge together with the charge for the distance covered. For a distance of 10 km, the charge paid is 105 and for a journey of 15 km, the charge paid is 155. How much does a person have to pay for traveling a distance of 25 km?

Answer 1

Answer:

255 rupees

Step-by-step explanation:

Let x be the fixed charge and y be the additional charge per km,

Thus, the charge for 10 km,

x + 10 y,

And, the charge for 15 km,

x + 15 y

According to the question,

x + 10 y = 105 -------(1)

x + 15 y = 155 --------(2),

Equation (2) - Equation (1),

5 y = 50

⇒ y = 10,

From Equation (1),

We get, x = 5

Hence,  the charges for 25 km = x + 25 y = 5 + 25 × 10 = 5 + 250 = 255 rupees.

Answer 2

Answer:

Step-by-step explanation:

Given :-

For a distance of 10 km, the charge paid is Rs 105.

For a distance of 15 km, the charge paid is Rs 155.          

Solution :-

Let the fixed charge for taxi = Rs x                  

And variable cost per km = Rs y                  

Total cost = fixed charge + variable charge                  

According to the Question,              

x + 10y = 105 … (i)                  

x = 105 - 10y                  

         

x + 15y = 155                  

Putting the value of x we get                  

105 - 10y + 15y = 155                  

5y = 155 - 105                  

5y = 50                  

Dividing by 5, we get                  

y = 50/5 = 10                  

Putting this value in equation (i) we get                  

x = 105 - 10 × 10                  

x = 5                  

Cost for traveling a distance of 25 km                  

= x + 25y                  

= 5 + 25 × 10                  

= 5 + 250                  

= Rs. 255    

             

Hence, A person has to pay Rs 255 for 25 Km.