Question

the taxi charges in a city of fixed charge first kilometre is 15 rupees after each Kilometre 5 rupees is increases passenger Travels 8 km what is the total cost to be paid​

Answer 1

Let fixed charge be Rs x and charge per km be Rs y.

⇒x+10y=105...(1)

⇒x+15y=155..(2).

Now From eq 2

⇒15y=155−x

⇒y=

15

155−x

...(3)

Substituting y from eq3 in eq1

⇒x+

15

10(155−x)

=105

⇒15x+1550−10x=1575

⇒5x=1575−1550

⇒5x=25

⇒x=5

Substituting x in eq2

⇒5+15y=155

⇒15y=155−5

⇒15y=150

⇒y=10

Hence x=5 and y=10

Fixed charge is Rs.55 and the charge per kilometer is Rs.1010

For 2525 km person have to pay = 5+10×25=255Rs.