The taxi charges in Hyderabad are fixed, along with the charge for the distance covered. For a distance of 10 km, the charge is rs.220.for a journey of 15km the charge paid is rs.310. What are the fixed and charge per km
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i. Let the fixed charge be x.
Let the charges per km be y.
Total charges to be paid will be the sum of the fixed charges and the charges per km.
For 10kms, the amount paid is ₹220.
x + 10y = 220 …I
For 15kms, the amount paid is ₹ 310
x + 15y = 310 …II
Solving I and II we get
x + 10y = 220
x + 15y = 310
- - -
-5y = -90
y = 18
Substituting the value of y in Eq. I we get
x + 10(18) = 220
x = 220 – 180
x = 40
The Fixed charge are ₹ 40 and the charges per km are ₹18
ii. For 25 km ,
total = 40 + 25(18) = 40 + 450 = 490
hence, for 25 km, the taxi fare is 490
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