the taxi charges in hyderabad are fixed along with the charge for the distance covered. for a distance of 10 km the charge paid is 220. for a journey of 15km charges paid is 310. what are the fixed charges and charge per km? how much does a person have to pay for travelling a distance of 25km ?
Answers
Answered by
62
let fixed charge be x
let charge per km be y
so,
x+10y=220
and x+15y=310
solving the equations, we have
y=Rs18, x=Rs 40
for a distance of 25 km, person have to pay (40+25*18)=Rs 490
sannidichaitu:
how can u say x = 40
substituting the value of y in any equation will give you the value of x. x+10y=220, so x=220-180, x=40.
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Answered by
22
i. Let the fixed charge be x.
Let the charges per km be y.
Total charges to be paid will be the sum of the fixed charges and the charges per km.
For 10kms, the amount paid is ₹220.
x + 10y = 220 …I
For 15kms, the amount paid is ₹ 310
x + 15y = 310 …II
Solving I and II we get
x + 10y = 220
x + 15y = 310
- - -
-5y = -90
y = 18
Substituting the value of y in Eq. I we get
x + 10(18) = 220
x = 220 – 180
x = 40
The Fixed charge are ₹ 40 and the charges per km are ₹18
ii. For 25 km ,
total = 40 + 25(18) = 40 + 450 = 490
hence, for 25 km, the taxi fare is 490
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