Question

the taxi charges in Hyderabad are fixed along with the charge for the distance covered .upto frist 3km you will be charged a certain minimum amount . from there onwards you have to pay additionally for every kilometer travelled for the frist 10km the charge paid is 166 rupee's for journey of 15 km the charge paid is 265 rupee's.
what are the fixed charge per km.
How much does a person have to pay for traveling a distance of 25 km​

Answer 1

Answer:

( i ) Fixed charges is 40 and charge per km is 18

( ii ) For travelling a distance of 25 km person has to pay 436.

Step-by-step explanation:

Let the fixed amount be x.

and let additional charge for travelling each kilometer be y.

Then, According to the question

x + (10 - 3)y = 166         {∵ travelling charge is fixed for first 3 km)

⇒ x + 7y = 166    → ( 1 )

x + (15 - 3)y = 256         {∵ travelling charge is fixed for first 3 km)

⇒ x + 12y = 256    → ( 2 )

Solving equations (1) & ( 2). We get,

x = 40 and y = 18

( i )- Hence fixed charge is 40

and charge per km be 18.

( ii )- For travelling a distance of 25 km person has to pay 40 + 22 × 18 = 436.

Answer 2

Answer:

₹ 463

Step-by-step explanation:

let the fixed charge for first 3 km be ₹ x and the the additional charge for every kilometer travelled be ₹ y.

Then,

x + (10-3)y = 166

=> x + 7y = 166 -------equation (1)

x + (15-3)y = 265

=> x + 12y = 265 -------equation (2)

Now, subtract equation (1) from (2).

(x + 7y) - (x + 12y) = 166-265

=> x + 7y - x - 12y = -99

=> x - x + 7y - 12y = -99

=> - 5y = -99

=> y = -99/-5

=> y = 19.8

Now, x + 7y = 166

=> x = 166-7y

So, x= 166 - (7 × 19.8) = 27.4

So , the amount paid by a person

for travelling 25 km = ₹ {27.4 + [19.8×(25 - 3)]}

= ₹ {27.4 + [19.8×22]}

= ₹ {27.4 + 435.6}

= ₹ 463