Question

The taxi fair in a city is as follows : For the first kilometer, the fare is Rs 8 and for the subsequent distance it is Rs 5 per km. Taking the distance covered as x km and fare as Rs y, write a linear equation for this information and draw it's graph too. ​

Answer 1

Answer:

8+5x=y

Step-by-step explanation:

Because first km is 8 rs per km and remaining is 5rs for remaining km.

Answer 2

$\large{\boxed{\mathfrak{\purple{Linear~Equation}}}}$

Let the distance be x

Let the fare for 1st km be ₹8

Let the fare of subsequent km be ₹5

ATQ

Distance = X

Taxi fare= ₹ Y

Solution:-

$8 + 5(x - 1) = y$

$8 + 5x + ( - 5x) = y$

$- 5x = 8 + ( - 5) = y$

$- 5x = 3 = y$

$5x - y + 3 = 0$