Question

The taxi fair is Rs.14, for first km and Rs.2
for each additional km what will be the
fair for 10 kms.
a) Rs.30
b) Rs.31
c) Rs.32
d) Rs.33​

Answer 1

Answer:

© 32

Step-by-step explanation:

14,14+2=16,14+2+2=18

14,16,18…

A10=a+(n-1)d

a=14. d=2

=A10=14+(9)2

=14+18

=32

Answer 2

Answer:

₹ 32

Step-by-step explanation:

This question is on Arithmetic Progression.

Here A1 is 14, A2 is 16 and Common Difference (D) is 2

So, we have to find for 10 km

Here,

An = A + (n-1) d

A10 = 14 + (10-1)2

A10 = 14 + 9x2

A10 = 14+18

A10 = 32

:- Hence, the answer will be ₹32.

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