Question

the taxi fair is rs 14 for the first kilometre and rs 2 in each additional kilometre what will be the fair for the 10 kilometre ​

Answer 1

Step-by-step explanation:

Taxi fare for first kilometer =14

Taxi fare for two kilometers =14+2=16

Taxi fare for three kilometres =16+2=18

And so on....

This forms an AP with first term a=14 and common difference d=2

We know

a

n

=a+(n−1)d

⇒a

10

=14+(10−1)2

⇒a

10

=14+18

⇒a

10

=32

⇒ taxi fare for first ten kilometres is Rs 32

Answer 2

Answer:

Step-by-step explanation:

Taxi fare for first kilometer =14

Taxi fare for two kilometers =14+2=16

Taxi fare for three kilometres =16+2=18

And so on....

This forms an AP with first term a=14 and common difference d=2

We know

an   =a+(n−1)d

⇒a10  =14+(10−1)2

⇒a 10  =14+18

⇒a10  =32

⇒ taxi fare for first ten kilometres is Rs 32

Hope it helps...

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