The taxi fare after each kilometers, when the fare is Rs. 15 for the first kilometer and Rs. 8 for each additional kilometers. Find the total fare for 21 kilometers.
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Answer:
False,because the total fare after each km is 15.
From the question above,
t₁ = 15,
t₂ = 23,
t₃ = 31,
t₄ = 39.
Calculating the difference, we get,
t₂ - t₁ = 23 - 15 = 8
t₃ - t₂ = 31 - 23 = 8
t₄ - t₃ = 39 - 31 = 8
Since, each of the successive terms of the given list have the same difference (d=8).
Therefore, the total fare after each km forms an AP.
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First kilometer -15
Other Twenty kilometres -20×8=160
160+15= 315
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