The taxi fare after each kilometers, when the fare is Rs. 15 for the first kilometer and Rs. 8 for each additional kilometer s. Find the total fare for 21 kilometer s.
pls give answer step by step
Answers
Answer:
t4 = 39
Step-by-step explanation:
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The taxi fare after each km, when the fare is Rs 15 for the first km and Rs 8 for each additional km, does not form an AP as the total fare (in Rs) after each km is 15, 8, 8, 8, ... Is the statement true? Give reasons
Solution:
An arithmetic progression (AP) is a sequence where the two consecutive terms have the same common difference. It is obtained by adding the same fixed number to its previous term.
From the question above,
False,because the total fare after each km is 15.
From the question above,
t₁ = 15,
t₂ = 23,
t₃ = 31,
t₄ = 39.
Calculating the difference, we get,
t₂ - t₁ = 23 - 15 = 8
t₃ - t₂ = 31 - 23 = 8
t₄ - t₃ = 39 - 31 = 8
Since, each of the successive terms of the given list have the same difference (d=8).
Therefore, the total fare after each km forms an AP.