Question

the taxi fare after each km when fare is 15 RS for the first 8 km for each additional kk​

Answer 1

Step-by-step explanation:

The linear equation will be

15+8x=y.

Answer 2

Answer:

We can write the given condition as;

Taxi fare for 1 km = 15

Taxi fare for first 2 kms = 15+8 = 23

Taxi fare for first 3 kms = 23+8 = 31

Taxi fare for first 4 kms = 31+8 = 39

And so on……

Thus, 15, 23, 31, 39 … forms an A.P. because every next term is 8 more than the preceding term.

Step-by-step explanation:

Hope this helps you ✌️