Question

The taxi fare after each km when the fare is ` 15 for the first km and ` 8 for each

additional km.​

Answer 1

Answer:

let fare be x

= rate × number of km

let travelled km be y

then x = 16(y-1) + 8y

Hope , it may help you

Answer 2

Answer:

$\: \: \sf \: \: a_1 = a = \: Rs.15 \\ \\ \\ \: \: \sf \: \: a_2 = a + d = 15 + 8 = \: Rs.23 \\ \\ \\ \: \: \sf \: \: a_3 = 23 + 8 = Rs.31 \\ \\ \\ \large{ \boxed{ \sf{ \: \therefore \: \: list \: of \: fares \: is \: 15, \: 23 \: and \: 31}}}$

Now,

$\\ \sf \: a_2 \: - \: a_1 \: = \: Rs. \: 23 - Rs. \: 15 = Rs. \: 8 \\ \\ \\ \sf \: a_3 \: - \: a_2= \: Rs. \: 31- \: Rs. \: 23 = Rs. \: 8 \\ \\ \\ \qquad \large \sf \because \: a_2 \: - \: a_1 \: = a_3 \: - \: a_2$

Therefore, the list forms an AP.