Question

the taxi fare after each km when the fare is ₹ 15 for the first km and ₹8 for each additional km​

Answer 1

Answer:

ANSWER

The taxi fare for first km=15

The taxi fare for 2nd km=15+8=23

The taxi fare for 3rd km=15+8+8=31 and so on,

Therefore, the taxi fare form the sequence 15,23,31,...

Clearly, it is an AP with first term a=15 and common difference d=8

Therefore, answer is 0.

Step-by-step explanation:

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Answer 2

Answer:

We can write the given condition as;

Taxi fare for 1 km = 15

Taxi fare for first 2 kms = 15+8 = 23

Taxi fare for first 3 kms = 23+8 = 31

Taxi fare for first 4 kms = 31+8 = 39

And so on……

Thus, 15, 23, 31, 39 … forms an A.P. because every next term is 8 more than the preceding term.

Step-by-step explanation:

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