The taxi fare after each km, when the fare is 15 for the first km and ₹8 for each additional km, does not form an AP as the total fare (in ₹ 3) after each km is 15, 8, 8, 8,.... Is the statement true? Give reasons.
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Answered by
1
Answer:
Yes,
if crossing 1 kilometre ₹8,₹8
Answered by
1
Answer:
No, because the total fare (in ?) after each km is 15,(15+ 8), (15 + 2 x 8), (15+ 3 x 8),…= 15,23, 31, 39,…
Let t1 = 15,t2 = 23,t3 = 31 and t4 = 39
Now, t2 - t1 = 23 - 15 = 8
t3 - t2 = 31 - 23 = 8
t4 - t3 = 39 - 31 = 8
Since, all the successive terms of the given list have same difference i.e., common difference = 8
Hence, the total fare after each km form an AP.
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