Question

the taxi fare after each km when the fare is rs.15 for the first km and rs.8 for each additional km ??


ARITHMETIC PROGRESSION​

Answer 1

Answer:

sk what to do in this question

Answer 2

We can write the given condition as;

Taxi fare for 1 km = 15

Taxi fare for first 2 kms = 15+8 = 23  

Taxi fare for first 3 kms = 23+8 = 31

Taxi fare for first 4 kms = 31+8 = 39

And so on……

Thus, 15, 23, 31, 39 … forms an A.P. because every next term is 8 more than the preceding term.