Question

the taxi fare after each km when the fare is Rs 15 for the first km and Rs 8 for each additional km​

Answer 1

Answer:

after each km is 15,(15+ 8), (15 + 2 x 8), (15+ 3 x 8),… = 15,23, 31, 39,… Hence, the total fare after each km form an AP

Answer 2

We can write the given condition as;

Taxi fare for 1 km = 15

Taxi fare for first 2 kms = 15+8 = 23

Taxi fare for first 3 kms = 23+8 = 31

Taxi fare for first 4 kms = 31+8 = 39

And so on……

Thus, 15, 23, 31, 39 … forms an A.P. because every next term is 8 more than the preceding term.