the taxi fare after each km when the fare is rs15 for the first km and rs 8 for each additional km
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what is the question????
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We can write the given condition as;
Taxi fare for 1 km = 15
Taxi fare for first 2 kms = 15+8 = 23
Taxi fare for first 3 kms = 23+8 = 31
Taxi fare for first 4 kms = 31+8 = 39
And so on……
Thus, 15, 23, 31, 39 … forms an A.P. because every next term is 8 more than the preceding term.
Step-by-step explanation:
Hope this helps you ✌️
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