Question

The taxi fare after each km when the fare is rupess 15 for the first km and rupess 8 for each additional km

Answer 1

Answer:

let the total distance= x km.

Total fare= Rs. y

y=1 x 8 + (x-1) x 5

y= 8+5x -5

y= 5x+ 3

5x -y+ 3 = 0

Here is you answer mate , please mark as brainliest.

Answer 2

Answer:

hey mate here is your answer....

Step-by-step explanation:

➡️ It can be observed that taxi fare for 1st km= ₹15

➡️ Taxi fare for 2nd km = 15 + 8 = ₹23

➡️ Taxi fare for first 3km = 23 + 8 = ₹31

➡️ Taxi fare for first 4 km = 31 + 8 = ₹39

▶️ Clearly 15, 23, 31, 39 forms an AP because every term is 8 more than the preceding term.

Hope it helps!☺️