The taxi fare in a city as follows for the first kilometer, the fare is 10 and for the subsequent distance, it is ` 6 per km. Taking the distance covered as x km and total fare as y draw the graph. Find the total fare for 15 km.
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Answer:
The person has to pay ₹94 for 15 kilometers.
Note: Kindly look at the photo for the graph.
Step-by-step explanation:
As per the question, the equation will be:
y=6(x-1)+10
This is because, total distance covered is 'x'. ₹10 is allotted for the 1st kilometer and ₹6 for the subsequent kilometers.
So, x-1 is the remaining kilometers that must be multiplied by 6 and then add ₹10.
y=6x-6+10
y=6x+4 is the required equation.
For 15km:
x=15km.
Now, substitute x=15 in the drawn equation.
∴y=6×15 +4
y=90+4
y=94
Therefore, for 15 kilometers, the person has to pay ₹94.
Check (without equation):
1st kilometer- ₹10
15-1=14
next 14 kilometers- 6×14 = ₹84
Therefore for 15 km, 10+84= ₹94
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