The taxi fare in a city in as follows... For first kilometre,the fare is Rs 8 and the subsequent distance it is Rs 4 per kilometre and total fare as Rs y write the linear equation for this information and it's graph
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Step-by-step explanation:
Given: Distance travelled =x km
total fare =Rs. y
Total fare =fair for first km+fare for remaining distance
Therefore, the equation is: y= 8+5×(x-1)=> y=x+3
For the graph:
putting x=1,we have,y=1+3=>y=4
putting x=2,we have,y=2+3=>y=5
putting x=3,we have,y=3+3=>y=6
Hence,A(1,8),B(2,13),C(3,18)
Hope this helps you .......
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