the taxi fare in a city is a s follows :
for the 1st km the fare is Rs.8 and for the subsequent distance it is Rs.5 per km.
taking the distance covered as Rs.x and total fare as Rs.y,
write a linear equation for this information.
Answers
Answered by
6
Let the total distance covered by the taxi = x km
Fare for the left distance = Rs (x -1) 5
So, the total fare of the taxi = [8 + (x - 1) 5]RS
So the equation will be,
y = 8 + 5x - 5
=> y = 5x + 3
=> 5x - y + 3 = 0 (ans)
Fare for the left distance = Rs (x -1) 5
So, the total fare of the taxi = [8 + (x - 1) 5]RS
So the equation will be,
y = 8 + 5x - 5
=> y = 5x + 3
=> 5x - y + 3 = 0 (ans)
kareen:
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Answered by
0
the answer is
5x - y + 3 = 0
5x - y + 3 = 0
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