Question

The taxi fare in a city is as follow for the first kilometers the fare is Rs 8 and for the subsequent distance it Rs 5 per km taking the distance covered as x km and total fare as Rs y write a linear equations for this information and it's graphs
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Answer 1

Step-by-step explanation:

ANSWER

x 0 1 2

y 3 8 13

Taxi fare for first kilometer = Rs. 8

Taxi fare for subsequent distance = Rs. 5

Total distance covered =x

Total fare =y

Since the fare for first kilometer = Rs.8

According to problem,

Fare for (x–1) kilometer = 5(x−1)

So, the total fare y=5(x−1)+8

⇒y=5(x−1)+8

⇒y=5x–5+8. I HOPE YOU UNDERSTOOD

⇒y=5x+3

Hence, y=5x+3 is the required linear equation.

Now the equation is

y=5x+3 ...(1)

Now, putting the value x=0 in (1)

y=5×0+3

y=0+3=3 So the solution is (0,3)

Putting the value x=1 in (1)

y=5×1+3

y=5+3=8. So the solution is (1,8)

Putting the value x=2 in (1)

y=5×2+3

y=10+3=13. So the solution is (2,13)

Answer 2

Let,

Distance be x

Fare for 1st km = ₹8

Fare for subsequent km= ₹5

ATQ

Distance = x km

Taxi fare = ₹ y

Solution-

➩ $8 + 5(x - 1) = y$

➩$8 + 5 + ( - 5x) = y$

➩$- 5x = ( - 5) + 8 = y$

➩ $- 5x = 3 = y$

➩$y + 5x = 3$

$\therefore$ $5x - y = 3$

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