Question

THE TAXI FARE IN A CITY IS AS FOLLOW :-
FOR THE FIRST KILOMETER THE FARE IS RS 8 AND FOR THE SUBSEQUENT DISTANCE IT IS RS 5 PER KM............TAKING TOTAL DISTANCE COVERED AS RS.x AND TOTAL FARE AS RS.y ,A LINEAR EQUATION FOR THIS INFORMATION AND DRAW ITS GRAPH [graph is necessary]
​

Answer 1

Answer:

Step-by-step explanation:

I will answer the question when you mark me in brainlist    

Answer 2

:

Mark Me As Brainliest And Thank Me If The Answer Is Useful.

-- :

x 0  1 2

y 3 8  13

Taxi fare for first kilometer = Rs. 8

Taxi fare for subsequent distance = Rs. 5

Total distance covered =x

Total fare =y

Since the fare for first kilometer = Rs.8

According to problem,

Fare for (x–1) kilometer = 5(x−1)

So, the total fare y=5(x−1)+8

⇒y=5(x−1)+8

⇒y=5x–5+8

⇒y=5x+3

Hence, y=5x+3 is the required linear equation.

Now the equation is

y=5x+3    ...(1)

Now, putting the value x=0 in (1)

y=5×0+3

y=0+3=3 So the solution is (0,3)

Putting the value x=1 in (1)

y=5×1+3

y=5+3=8. So the solution is (1,8)

Putting the value x=2 in (1)

y=5×2+3

y=10+3=13. So the solution is (2,13)