The taxi fare in a city is as follow : for the first km , the fare is Rs5 and for the subsequent distance it is Rs 5 per km . Taking the distance covered as x km and total fare as Rs y , Write a linear equation for this information , and draw its graph .
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Answer:
y = 5x+3
Step-by-step explanation:
Fare for 1st kilometre = Rs. 8
Fare for subsequent distance = Rs. 5 per km
Let, Distance Covered be = x km
And, Total Fare be = Rs. y
Therefore,
y = 8X1+5(x-1)
y = 8+5x-5
y = 5x+3 (ans)
Graph :
Let, x = 1
y = 5x1+3
y = 8
(1,8)
Let, x = 2
y = 5x2+3
y = 13
(2,13)
For Graph, see the pic attached.
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