Question

The taxi fare in a city is as follows : for the 1st 5 km the fare is rupees 8 , and for the subsequent diatance it is rupees 5 per km . Taking the distance as x and the total fare as rupees y write the linear equation for the information.

Plzz answer the question and no irrelevant answers .
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Answer 1

Answer:

8+(x-5)5=y

Step-by-step explanation:

as per ques ,

first 5 km cost 8 rs and then for each km rs5 so,total fare=8+(x-5)

Answer 2

ANSWER

x 0 1 2

y 3 8 13

Taxi fare for first kilometer = Rs. 8

Taxi fare for subsequent distance = Rs. 5

Total distance covered =x

Total fare =y

Since the fare for first kilometer = Rs.8

According to problem,

Fare for (x–1) kilometer = 5(x−1)

So, the total fare y=5(x−1)+8

⇒y=5(x−1)+8

⇒y=5x–5+8

⇒y=5x+3

Hence, y=5x+3 is the required linear equation.

Now the equation is

y=5x+3 ...(1)

Now, putting the value x=0 in (1)

y=5×0+3

y=0+3=3 So the solution is (0,3)

Putting the value x=1 in (1)

y=5×1+3

y=5+3=8. So the solution is (1,8)

Putting the value x=2 in (1)

y=5×2+3

y=10+3=13. So the solution is (2,13)

solution