The taxi fare in a city is as follows:For the 1st km,the fare is Rs 8 and for the subsequent distance covered as x km and total fare as Rs y,write a linear equation for this information,and draw it's graph
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The equation is 5x+3 put the value of x in subsequent distance
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⇒ Let the total fare be = y Rs
⇒ Distance covered be = x km
⇒ For first subsequent distance (x - 1) km fare = 5(x - 1)
⇒ y = 8 + 5 (x - 1)
⇒ y = 8 + 5x - 5
⇒ y = 5x + 3
⇒ The coordinates of the following linear equation
1) x = 0, y = 3 (0,3)
2) x = 1, y = 8 (1,8)
3) x = 2, y = 13 (2,13)
4) x = 3, y = 18 (3,18)
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