Question

the taxi fare in a city is as follows for the first kilometre the fare is rs.8 and for the subsequent distance it is rs.5 per km. taking the distance covered as x km and fare as rs.y write a linear equation.​

Answer 1

Step-by-step explanation:

The linear equation is

(8*1)+(x-1)*5=y

5x-5+8=y

5x-y=-3

y-5x=3

Answer 2

✯✯ QUESTION ✯✯

The taxi fare in a city is as follows for the first kilometre the fare is rs.8 and for the subsequent distance it is rs.5 per km. Taking the distance covered as x km and fare as rs.y write a linear equation..

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✰✰ ANSWER ✰✰

$\longmapsto\tt{Let\:the\:distance\:covered=x\:km}$

$\longmapsto\tt{Fare\:for\:travelling=y\:km}$

$\longmapsto\tt{Fare\:for\:1st\:km=Rs.8}$

$\longmapsto\tt{Fare\:for\:subsequent\:km=Rs.5 /km}$

➥Now ,

$\longmapsto\tt{y=8\times{1}+(x-1)\times{(-5)}}$

$\longmapsto\tt{y=8+5x-5}$

$\longmapsto\tt{y=5x+8-5}$

$\longmapsto\tt\boxed{y=5x+3}$

☛So , The linear equation is y=5x+3...